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Fix using pow instead of pow_base

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thepaperpilot 2023-04-23 12:47:49 -05:00
parent e3fe1fcc27
commit 00b87c2cc1
2 changed files with 3 additions and 3 deletions
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4
docs/guide/important-concepts/formulas.md
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@ -8,7 +8,7 @@ For example, a cost function like `Decimal.pow(this.amount, 1.05).times(100)` ca
const myRepeatable = createRepeatable(() => ({
requirements: createCostRequirement(() => ({
resource: points,
cost: Formula.variable(myRepeatable.amount).pow(1.05).times(100)
cost: Formula.variable(myRepeatable.amount).pow_base(1.05).times(100)
})),
maximize: true
}));
@ -22,7 +22,7 @@ For inverting and integrating, formulas should have a single variable, which ser
The variable is defined by wrapping the input to the formula in `Formula.variable`. In the cost requirement example above, the repeatable's `amount` is the input to the variable. That means inverting the function would calculate the amount based on the cost, and integrating would be finding the area under the curve where the repeatable's `amount` is the x axis and the output of the formula is the y axis.
If the cost formula had not marked a variable, e.g. `Formula.pow(myRepeatable.amount, 1.05).times(100)` then the formula would not be invertible or integrable, and would throw an error if either operation was tried. While `evaluate()` will work as expected, passing a value to `evaluate()` will not, as it will not know what value to override.
If the cost formula had not marked a variable, e.g. `Formula.pow(1.05, myRepeatable.amount).times(100)` then the formula would not be invertible or integrable, and would throw an error if either operation was tried. While `evaluate()` will work as expected, passing a value to `evaluate()` will not, as it will not know what value to override.
### Invertibility and Integrability

2
docs/guide/migrations/0-6.md
View file

@ -66,7 +66,7 @@ When coupled with the formulas system, they also allow for scaling requirements
const myRepeatable = createRepeatable(() => ({
requirements: createCostRequirement(() => ({
resource: points,
cost: Formula.variable(myRepeatable.amount).pow(1.05).times(100)
cost: Formula.variable(myRepeatable.amount).pow_base(1.05).times(100)
})),
maximize: true
}));